Important Update: This info has been changed, due to more in depth investigations proving that my initial workings were wrong. It should now be 100% correct. Please contact me via the link above if you find errors.
Like me, you might find the channel you want isn't listed on the truth chart. For some reason Icom decided to omit several channels from the Truth Chart, 62 in this example. You must always program the radio with the RX frequency, then on duplex channels, the duplex diode subtracts 4.600 MHz from the TX frequency.
The base frequency of the matrix board, with no diodes is 160.000 MHz.
Duplex subtracts 4.600 MHz on TX
N400 subtracts : 5.000 MHz
N200 appears unused
N100 adds : 1.250 MHz
N80 adds : 1.000 MHz
N40 adds : .500 MHz
N20 adds : .250 MHz
N10 adds : .125 MHz
N8 adds : .100 MHz
N4 adds : .050 MHz
N2 adds : .025 MHz
So, how do you work it out? Don't panic, you don't need a maths degree, though having a calculator handy can help!
The frequency we want (ch62) = 160.725 MHz
The base frequency = 160.000 MHz
Add a diode to N40 : + .500 = 160.500 MHz
Add a diode to N10 : + .125 = 160.625 MHz
Add a diode to N8 : + .100 = 160.725 MHz on RX
Add a duplex diode : - 4.600 = 156.125 MHz on TX
That's it! You should be able to work out the correct diode placement for any frequency within the band. Just remember you can only use each N number once in your calculations -like on Countdown! :-)
If there is already a diode in one of the places you wish to use, you can just leave it there and don't need to replace it. If there are diodes in places not in your calculations, they
must be removed.